python从视频中提取内容,python快速读取大文件数据
我想要做的是从音频或视频文件获取元数据并将其保存到数据库记录,到目前为止唯一的方法是使用子进程将AVCONV保存到文件中。打开电话然后读取该文件,是有任何库可以做到这一点,以节省一些步骤?我找不到用Pydub或PySox来做这件事的方法。这里是我使用的简单化的初学者代码,它可以工作,并将比特率,持续时间等信息放入变量audio_info中,并将元数据放入元数据中。 OGG输出的工作方式与我测试的其他格式不同(这是一大堆视频和音频!)。
try:
p = subprocess.Popen(["avconv" , "-i" , music_file], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
out, err = p.communicate()
retcode = p.wait()
except IOError,e:
pass
extension = uploaded_music_file[-3:]
if "ogg" not in [err , extension]:
if "Metadata:" in err:
list = err.split("Metadata:")
holder = list[1].split("Duration:")
metadata = holder[0]
audio_info = holder[1].replace("At least one output file must be specified","")
print metadata
print audio_info
else:
list = err.split("Duration:")
audio_info = list[1].replace("At least one output file must be specified","")
print "No Metadata"
print audio_info
else:
list = err.split("Duration:")
if "Metadata:" in list[1]:
data = list[1].split("Metadata:")
metadata = data[1].replace("At least one output file must be specified","")
audio_info = data[0]
print metadata
print audio_info
else:
audio_info = list[1].replace("At least one output file must be specified","")
print "No Metadata"
print audio_info
if (audio_info):
print "AUDIO INFO:"
cursor.execute("UPDATE songDB SET audio_info = %s WHERE id = %s" ,[ audio_info , song_id ] )
if (metadata):
print "METADATA:"
cursor.execute("songDB pack_song SET metadata = %s WHERE id = %s" ,[ metadata , song_id ] )